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Thus, the update z nl i + 1 further simplifies to z nl i + 1 = x n, nl i + 1 + x tran ( l ), nl i + 1 27 (27).
Hence, the global variable update z nl i + 1 is simply the average of its local copies x n, nl i + 1 and x tran ( l ), nl i + 1.
Moreover, by substituting z nl i + 1 in (20 k, we can show that the sum of the dual variables u n, nl i + u tran ( l ), nl i is equal to zero.
Hence, by setting the gradient of (25) with respect to z nl equal to zero, we can get the solution z nl ⋆ which can be expressed as z nl ⋆ = x n, nl i + 1 + x tran ( l ), nl i + 1 + 1 ρ ( u n, nl i + u tran ( l ), nl i ) 2, (26).
In step 3, the neighboring BSs that are coupled by variable z nl, i.e., BS n and BS tran(l), exchange their local copies x n, nl i + 1 and x tran ( l ), nl i + 1.
Local copies x n, nl i + 1 and x tran ( l ), nl i + 1 are exchanged between the adjacent BS n and BS tran(l), while local copy α n is broadcasted to all other BSs.
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I've watched @nbcsnl since I was a baby.
@ReignOfApril @aurabogado @melissavcomedy @nbcsnl @SNLUpdate I also saved this gem and a few others.
This probability, denoted as R nls,x (i), is calculated as R nls, x i = R P r x, i ≥ LS _ thr = R H x, i ≥ LS _ thr P t = ∫ − ∞ ∞ Q LS _ thr P t − H ¯ x, i σ. 1 2 π σ e − G o 2 2 σ 2 d G o (29).
Experimental treatments applied in a split-plot design included four planting densities (1111, 833, 625 and 500 stems ha−1) and three poplar clones (NL-80351, I-69 and I-72).
To do that we measured the WF generated by a NL-GS, i.e., from the PSF generated by the two-photon excited fluorescent volume, inside the red-paint and then we compared it with the generated WF produced by a physical point source such as a fluorescent spherical bead of i) 1 µm and ii) 0.28 µm in diameter.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com