Sentence examples for n dir from inspiring English sources

The transmission rate ř n aDF is only limited by the rate ř n Dir if λ ̌ n ( S R ) < λ ̌ n ( S D ).

b Inverter station Table 2 Simulation results for a fault at F2 Location RF Pole Rectifier side Inverter side Result S m Dir S n Dir F2 0 + −0.19 0 −0.19 0 Normal - −11.01 1 −11.52 1 Internal.

b Inverter station Table 3 Simulation results for a fault at F3 Location RF Pole Rectifier side Inverter side Result S m Dir S n Dir F3 0 + −27.41 1 −27.66 1 Internal - −27.63 1 −27.72 1 Internal.

b Inverter station Table 4 Simulation results for a fault at F4 Location RF Pole Rectifier side Inverter side Result S m Dir S n Dir F4 0 + 23.73 −1 −14.01 1 External - 1.85 −1 −4.05 1 External.

b Inverter station Table 1 Simulation results for a fault at F1 Location RF Pole Rectifier side Inverter side Result S m Dir S n Dir   F1 300 + −1.96 1 −1.91 1 Internal - / / / / Normal.

On the other hand, if λ ̌ n ( S R ) > λ ̌ n ( S D ), the solution of the nDF in Equations (79) and (81) can be used because rate ř n nDF is always better than the rate ř n Dir of the direct path.

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Pitch ring (quarter of A n ), with dir being the azimuth (N, E, S, W).

Figure 4 shows the leakage effect of dir N 0 π i − v q T s N 0 and dir N 0 π i − λ v q T s N 0, where v q T s N0=0.4 and v q T s N0=0.5. Figure 4 Comparison between dir N 0 π i − λ v q T s N 0 and dir N 0 i − v q T s N 0. dir N 0 π i − λ v q T s N 0 has a quicker fade speed of side lobe and a smaller value of side lobe than dir N 0 i − v q T s N 0. (a) v q T s N0=0.4, λ=2.

From Equations 24 and 16, we find that dir N 0 π i − v q T s N 0 in Equation 16 is replaced into dir N 0 π i − λ v q T s N 0. So if v q T s N0=n/λ, dir N 0 π i − λ v q T s N 0 can be transformed into a Dirac function.