Sentence examples for mutant is neutral from inspiring English sources

Exact(4)

Although the WW domain (hYAP65 L30K mutant) is neutral overall, it forms a macro-dipole from the second turn (T2) (partially negative) to the first turn (T1) (partially positive) (Fig. S2).

Similar to the previous section, a mutant is neutral if its secondary structure is the same as that of the tRNAphe; otherwise, it is deleterious.

This means that the replacement probability, as a resident strategy, is at most 1 / N (which is the probability to be replaced if the mutant is neutral).

The formulation of the phenotypic error threshold itself is independent of this terminology.] To calculate the effective replication accuracy Q e = Q + Λ (1 - Q), we assume that a mutant is neutral iff there is no deleterious substitution: The effect of a substitution on the phenotype is independent of the other substitutions; i.e., no epistasis is assumed (the additive assumption).

Similar(56)

For our calculations, we also assume that all the mutants are neutral before the beginning of therapy.

If mutants with δ > 0 are only considered, positive epistasis occurs very rarely compared to additive deleterious case: No more than 0.5% of the mutants are neutral at d = 5 if they carry at least one deleterious substitution.

In that case, as long as | r - 1| N ≫ 1, A more subtle situation arises when the mutant B is neutral.

We first consider the viable mutants, that is, neutral ones and parasites, then we characterize the rest of the mutational neighborhood.

The wild type residue (Lysine) at codon 103 is positively charged while the mutant residue (Methionine) is neutral and more hydrophobic than the wild type residue.

The results were quite encouraging: while affinity of one double mutant (N96W + H222Y) is neutral and one (N96W + D124) affinity actually decreased, two double mutants, N96W with A114E and V35L, had affinity increased compared to WT.

If the mutant allele was neutral prior to the change in the selection scheme, ρ (x ) = C x Θ − 1 1 − x 1 − θ x − 1. (B3)Here, θ is the per-locus mutation rate, C = − 1 denotes a normalization constant where γ ˜ ≈ 0.577 is Euler's gamma, and ψ is the polygamma function.

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