Sentence examples for modules there exists from inspiring English sources

Exact(1)

In particular, comparing with SSN modules, there exists negative feedbacks in SSI modules caused by inhibitions, which makes the module structure and the reaction mechanism much more complicated.

Similar(59)

We say that M is a graded R-module if there exists a family of submodules {M g }g∈G of M such that M = ⊕g∈GM g and R g M h  ⊆ M gh for all g, h ∈ G, and we write h(M) = ∪g∈GM g.

A module- additive mapping is called a generalized module-   left derivation (resp., generalized module-   derivation) if there exists a module- left derivation (resp., module- derivation) such that (17).

Under a given set of operating conditions, there exists a module length (named as optimum module length) where the net thermal energy consumption and overall permeate productivity are optimum.

Also, the next lemma shows that there exists a module of finite uniform dimension without couniserial dimension.

Additionally: 1. L K ( m, n ) is universal, in the sense that if S is any K -algebra having module type ( m, n ), then there exists a nonzero K -algebra homomorphism φ : L K ( m, n ) → S.   2.

L K ( m, n ) is universal, in the sense that if S is any K -algebra having module type ( m, n ), then there exists a nonzero K -algebra homomorphism φ : L K ( m, n ) → S. L K ( m, n ) is simple ( i.e., has no nontrivial two-sided ideals ) if and only if m = 1.

It suffices to show that if ϕ ∈ F r Hom M o d ∞ (M, N ), then there exists a module K and homomorphisms π : M → K, ψ : K → N such that π ∈ F 1, ψ ∈ F r − 1 and ϕ = ψ ∘ π.

Recall that a QTAG-module M is (ω+1 -projective if there exists submodule N⊂H1(M) such that M/N is a direct sum of uniserial modules and a QTAG module M is (ω+1 -projective if there exists submodule N⊂H1k (M) such that M/N is a direct sum of uniserial modules [5].

3- It is assumed that there exists another location awareness module not implemented here, this module provides us with some important parameters like:   A.

Since (M) is finitely generated, there exists a right module (L) such that for some (k), (E(M) ^{k} cong M oplus L ).

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