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The full subcategory R of all regular modules is abelian.
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Therefore Q b is abelian, as required.
Obviously, C N ( b ) p ′ is abelian.
Likewise the group of 43,252,003,274,489,856,000 operations on Rubik's cube and the infinite group SO(3) of rotations of the sphere are not abelian, though the infinite group SO(2) of rotations of the circle is abelian.
It follows that C G ( a ) = M p ′ is abelian.
If G is abelian, each polynomial automorphism is of the form x↦x ε, and so P G) is abelian.
Assume that the corresponding commutant algebra C = comm is abelian.
If G is abelian, left and right translation by a group element are the same.
It rests on the observation of Beck [2] that the concept of a split-null extension has a natural definition in the categorical setting: if (X) is an object in a category ({mathcal {C}}), an (X -module is an abelian group in the comma category ({mathcal {C}}downarrow X -module
It remains to check that they are abelian groups.
Relations saying that (H_0) and (H_1) are Abelian groups of exponent p, and (H_2) is an Abelian group.
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