Sentence examples for module version from inspiring English sources

In study 2, however, we found no evidence to support an interaction between module version and level of student.

The results values are module ID, the creation time of the results value, module name, module version, and checked flag.

We introduce a class of Banach modules which are a module version of the BSE commutative Banach algebras considered by the author and Hatori.

The rough set LEM2 (Learning from Examples Module, version 2) algorithm generates a set of comprehensible decision rules that can be applied in a knowledge-based education system designed for interested parties.

To address research question 2 for study 2, we assessed students' expression of misconceptions in the classes that used either module version as indicated by their selection of distractor answer options on the graded questions (as in study 1).

Segmentation of raw copy numbers was calculated using the GLAD module (version 2).

Then, series of ambiguous sequence 'N' of the genomic scaffolds were filled using the software the GapCloser module version 1.12 (Luo et al. 2012).

They incorporated the following two individual models off-line: the GOCART solo-module version of the WRF coupled with chemistry (WRF Chem; Grell et al. 2005), and the National Aeronautics and Space Administration NASAA) Unified WRF (NU WRF; Peters-Lidard et al. 2015).

In the case d = 1, we get the following result which is the L 0 -module version of an intermediate value theorem.

Table 1 Terms explanation Terms Explanation ME/MN/AM Existing/new module/authentication module MF/CA Manufacturer/certificate authority Hash Hash function Sigx/Veryy Signature algorithm using x key/ Verification algorithm using y key Cert Certificate Kx_prv/Kx_pub Private key of X/public key of X MID/MN/MV Module identifier/module name/module version X_TS Time stamp values of X CF Checked flag.

Then by (1.4) it holds that 1 A j ∑ k = 1 N λ k X k j = 0 and since S j is a conditional simplex, 1 A j λ k = 0 for all j ∈ N and k = 1, …, N. From the fact that ( A j ) j ∈ N is a partition, it follows that λ k = 0 for all k = 1, …, N. We will prove the Brouwer fixed point theorem in the present setting using an L 0 -module version of Sperner's lemma.