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Therefore, is mean square continuous on.
We claim that π is mean square continuous on [ 0, ∞ ).
By the proof of Theorem 3.1, we can verify that S x + U y ∈ Λ when x, y ∈ Λ and S is mean square continuous.
Let (X t)) be a mean square differentiable second order stochastic process in (I=[t_{0},T]) and mean square continuous in it.
Let (X t)) be a second order stochastic process, mean square continuous on (I=[t_{0},T]), then there exists (etain I) such that int_{t_{0}}^{t}X s),ds=X eta) (t-t_{0}), quad t_{0}< t
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with x t) a quaternion continuous completely known signal and v t) a quaternion mean-square continuous Gaussian noise.
with x t) a mean-square continuous quaternion random signal and w0 t) the quaternion Q -proper Wiener process with parameter r0.
Also, if q n (t), n=1,…,4, are mean-square continuous signals, then an extension of the KL expansion to the quaternion field can be suggested [12].
Jeong [3] studied the same problem, provided that (f Itimes L_{2}rightarrow L_{2}) and (g:I^{p}times L_{2}rightarrow L_{2}) are fuzzy mean-square continuous functions.
The function g is said to be mean square uniformly continuous in I, if lim_{hrightarrow0}omega g,h)=0.
The performance of HMM GMR was verified based on the mean square error and continuous ranked probability score skill scores.
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