where |·| and ∥·∥2 denote the absolute value and Euclidean norm, respectively, and w max denotes the maximum element of w.
Identify the maximum element of each column, and corresponding row index k' denotes the assignment of that user to the i th sub-carrier.
Compute the maximum element of the vector ΔI j, i, max{ΔI j, i }, and remove a bit from the sub-carrier identified by the corresponding column index i.
Step 2: Find the maximum element of |g (i |, then get its column index as ( j=underset{nin left{1,2,cdots, Nright}}{ arg max}left|{boldsymbol{g}}^{(i)}(n right| ).
Without loss of generality, assuming that x m is the maximum element of { x j : j = 1, 2, 3, …, m }, that is, x j ⪯ x m, for j = 1, 2, 3, …, m. (4).
Since cl ( { x α } ) is totally ordered, and { x j : j = 1, 2, 3, …, m } ⊆ cl ( { x α } ), there is a maximum element of the finite subset { x j : j = 1, 2, 3, …, m }.
Given an initial guess (u^{(0)}), for (k=0,1,ldots ) , until ({u^{ k)}}) converges, compute begin{aligned} (omega I+C+iI u^{ k+1)}= omega I-D+C-T u^{ k)}+b, end{alI-D+C-T u^{ khere (omega =frac{d_{mI-D+C-T u^{ k}+b}) is thend{aligned (d_{min }) and (d_{max }), where (d_{min }) and (d_{max }) are the minimum and maximum elements of the diagonal matrix D.
Let Dmin and Dmax be the minimum and maximum elements of D, respectively.
The mesh had 73,269 cells with a maximum element size of 80 μm × 80 μm.
A grain approximately 15 μm across was meshed with a maximum element size of 0.69 μm, which from Eq. 49 corresponds to five mesh elements per interface width.
We study the problem of soliciting human crowd workers to find the maximum element in a set of objects, where each object has some unknown intrinsic quality measure.
