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In Section 5, we show that for a word wi of weight i, where i∈{100,112,164,176} the stabilizer (McL wi is a maximal subgroup of McL.
Hence (Mbigcap K) is a maximal subgroup of (K).
Hence (Mbigcap K) centralizes every maximal subgroup of (H).
Let (N_{0}) be a maximal subgroup of (N).
Hence (Hbigcap K) permutes with every maximal subgroup of (K).
Moreover (Mbigcap H) is a maximal subgroup of (H).
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We study the maximal subgroups of free idempotent generated semigroups on a biordered set by topological methods.
Notice that (H) does not permute with the maximal subgroups of (K).
Now we may assume that all maximal subgroups of (P) are (s -semipermutable in (G).
Since the other maximal subgroups of S do not contain subgroups isomorphic to (S_4) and H is not a power of a prime, we have that (Hcong S_3).
Since the indexes of the maximal subgroups of S containing I S divide t 1 and t 1 ∣ | Aut ( C ) |, we have that t 1 = 1.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.
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CEO of Professional Science Editing for Scientists @ prosciediting.com