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The channel model was characterized as a matrix product of transmitter, receiver, and scattering correlation matrices and the covariance feedback was used.
In this paper, we show that the interface pressure is equal to the trace of the matrix product of the curvature tensor and the Cauchy stress tensor in the tangent plane.
Then we have (Ain (X,Y_{T})) if and only if (C=Tcdot Ain (X,Y)), where C denotes the matrix product of T and A. If X and Y are B spaces and (Ain (X,Y_{T})) then Vert L_{A}Vert =Vert L_{C}Vert.
(a) Then we have (Ain (X,Y_{T})) if and only if (C=Tcdot Ain (X,Y)), where C denotes the matrix product of T and A. (b) If X and Y are B spaces and (Ain (X,Y_{T})) then Vert L_{A}Vert =Vert L_{C}Vert.
We denote the data matrix and the load matrix in the test phase by V t and H t. The data matrix V t contains the processed speech signal, and H t is found by minimising the Kullback-Leibler divergence between V t and the matrix product of the acquired W a ∗ and the unknown H t. H t ∗ = arg min H t D KL V t | | W a ∗ H t (5).
The n-mode (matrix) product of a tensor F ∈ C I 1 × I 2 ⋯ × I N with a matrix U J × I n is denoted by F × n U and is of size I 1 × ⋯ × I n − 1 × J × I n + 1 × ⋯ I N. Elementwise, we have F × n U i 1 ⋯ i n − 1 j i n + 1 ⋯ i N = ∑ i n = 1 I n f i 1 i 2 ⋯ i N u j i n.
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This paper investigates the computation of matrix product on both partially pipelined and fully pipelined modular linear arrays.
So far, the cross-matrix product of the two sets of multidimensional variables has been widely used for the derivation of these variants.
Indeed, instead of focusing on the cross-matrix product of the two sets of multidimensional variables, we have used the product of the orthogonal projectors onto the space spanned by the columns of the two sets of multidimensional variables.
Create a new blank matrix that will mark the dimensions of the matrix product, the product of the two matrices.
The remaining matrix product, representing scaling of male contributions and transmission of the focal marker gene, has dominant eigenvalue f, with right eigenvector (1, f 1 − f ) ′.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com