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Then the matrix has the form (4.50).
Constructing that matrix has the complexity O(n 2).
Then the trace of matrix has the lower and upper bounds given by (3.1).
where the transformation matrix has the dimensions of, and is a bias parameter.
The noise covariance matrix has the same structure as in Example 1 (13).
If, then the trace of matrix has the lower and upper bounds given by (3.3).
(3) If, then the trace of matrix has the lower and upper bounds given by (3.4) .
The Fourier matrix has the property of F 3=Γ F=F −1=F H.
Inserting into (4.8), we want to prove that the resulting matrix has the form (4.7).
Here, the first matrix has the forward linkage vector as its diagonal elements and zero for the others, while the second matrix has the backward linkage vector as its diagonal elements and zero for the others.
This matrix has the same structure as the original, but the channel coefficients are now modified according to.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com