Sentence examples for matrices with equivalent from inspiring English sources

Exact(1)

We also considered matrices with equivalent sizes as those used in [3, 14] (Beowulf B2).

Similar(59)

Weak staining of calcified cartilage matrix but not chondrocytes or the surface matrix was evident with equivalent concentrations of rabbit IgG even in IL-1-stimulated cultures, and staining was abolished pre-absorption with the recombinant protein.

As is shown in [1] and used in [4] the algebraic eigenvalue problems for real-symmetric, banded matrices with bandwidth are equivalent to eigenvalue problems for self-adjoint Sturm-Liouville difference equations of order with Dirichlet boundary conditions.

One microliter of the analyte solution, along with equivalent matrix solution (HCCA), was mixed and applied onto 600 μm AnchorChip target for MALDI-TOF/TOF analysis.

The FRF of the housing, which was calculated from the equivalent matrices with the modified PMSM, showed satisfactory consistency with that from the modal testing.

The symmetric matrix (A=Soperatorname{diag}(lambda _{1},ldots,lambda_{n} S^{T}) is called a solution of SCRSIEP for (Lambda =(lambda_{1},ldots,lambda_{n})) associated with the typical orthogonal matrix S. Then we can say, by Theorem 2.2, that two solutions of the SCRSIEP for Λ associated with equivalent typical orthogonal matrices are permutationally similar to each other.

Zhang et al. 2014, 2015a, b) applied such 3D damaged stiffness matrix with the mentioned equivalent stress and displacement relationship to investigate the contribution of local details of the braiding architecture and the local stresses, strains, and damage mechanisms on the global response of braided composites.

Two graphs E and F are "flow equivalent" in case the collection of flows through E match up appropriately with the collection of flows through F. Two matrices with entries in Z + are called flow equivalent in case the directed graphs corresponding to the two matrices are flow equivalent.

The existence of the Green's matrix is then equivalent with the regularity of K, i.e. with the assumption det K ≠ 0. If this is satisfied, then H from (13) is given by the formula H = − K − 1 V , τ ∈ [ a, b ], and the Green's matrix takes the form G ( t, τ ) = { − K − 1 V , a ≤ t ≤ τ ≤ b, − K − 1 V + E, a ≤ τ < t ≤ b.

Performing the modularity analysis with the full, weighted partial correlation matrix produces equivalent results (also shown in S3).

Such Hadamard matrices are called equivalent.

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