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Exact(13)
Thus the mapping is quadratic.
Therefore, the mapping is quadratic.
By Lemma 2.1, the mapping is quadratic.
Since the mapping is quadratic (see [54, Lemma ]), we get that the mapping is quadratic.
By [45, Lemma 2.1], the mapping, : is quadratic.
By Proposition 2.1 (by letting ), the mapping is quadratic.
Similar(47)
It is proven in [8]; that for the vector spaces and and the fixed positive integer, the map is quadratic if and only if the following equality holds: (2.1).
Conversely, if a mapping f is quadratic, then it is obvious that f satisfies equation (2).
Conversely, if a mapping f is quadratic, then it is obvious that f satisfies (4).
δ is a quadratic mapping, δ is quadratic homogeneous, that is, δ ( λ a ) = λ 2 δ ( a ) for all a ∈ A and all, δ ( a b ) = δ ( a ) b 2 + a 2 δ ( b ) for all a, b ∈ A, δ ( a ∗ ) = δ ( a ) ∗ for all a ∈ A. Example 2.2 Let A be a commutative ∗-normed algebra.
The mapping Q is quadratic because it satisfies equation (1.2) as follows: ∥ D ˜ 1 Q ( x, y ) ∥ β = lim n → ∞ 1 | k | 2 n β ∥ D ˜ 1 f ( k n x, k n y ) ∥ β ≤ lim n → ∞ 1 | k | 2 n β φ ( k n x, k n y ) = 0. for all x, y ∈ X ; therefore, by Lemma 2.2, it is quadratic.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com