Sentence examples for map the translation from inspiring English sources

To demonstrate it, we map the translation initiation landscape of a Saccharomyces cerevisiae gene (RMD1) with a typical ATG sequence context profile.

Gene coordinates were used to map the translation start codon (ATG) and to extract the upstream sequences.

For each mRNA, in silico translation of the full sequence was performed using the Transeq software (20), and subsequent comparison of the results with the amino acid sequence of the reference protein allowed to map the translation start and stop sites coordinates of the reference ORF on its corresponding mRNA.

MAP is the translation table, which denotes the correspondence between the representative labels in the previous row and the provisional labels in the current row.

When there is no pseudo-symmetry of the first or special kind (and there is no metric specialization), there is also no obvious mismatch between (or detachment of) the visible point symmetry around the center of this map and the translation symmetry that is governed by the metrical properties of the extracted lattice parameters.

This can happen because nodes were deleted from the map during the translation.

However, a problem with automatic layout is that changes of the map during the translation can disturb the layout in some manner.

The first prerequisite for this mapping was the translation of the MDMC attributes and terms to the English language as there is not a Czech version of SNOMED CT [ 41].

Two adjacent genes were defined as in an operon if they had fully contiguous (i.e., non-zero) read mapping from the translation start site of the upstream gene to the translation stop site of the downstream gene in both WT/CO2 RNA samples [ 28].

We observe that, from the fact that Map 0, (D A, D A ) is an increasing filtration, and by part (iii) of Lemma 3.9, (3.2) σ k − ≔ h d i a g ± (1 + τ ± + τ ± 2 + ⋯ + τ ± k − 1 ) ∈ Map (B A, B A ) 0, k (B D A, B D A ). Finally, we note that for any l, as a map in C h the translation map satisfies (3.3) τ − k (B (k, l ) D A ) = 0. We now use induction to prove our theorem.

SBGN map creation and editing; SBGN map validation; and the translation of networks into SBGN.