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have at most finitely many common zeros.
Thus, y 1 ( z ) and y 2 ( z ) have at most finitely many common zeros.
ByLemma 2.1, we see that A ( z ) + f 2 ( z ) and 1 − f ( z ) have at most finitely many common zeros.
Using the same discussion as Lemma 2.1, we easily see that f ( z ) + A ( z ) − α 1 + α and 1 − f ( z ) have at most finitely many common zeros.
Using the same discussion as Lemma 2.1, we easily see that f 2 ( z ) + α f ( z ) + A ( z ) − α and 1 − f ( z ) have at most finitely many common zeros.
Using the same discussion as Lemma 2.1, we easily see that ( 1 + α ) f 2 ( z ) − α f ( z ) + A ( z ) and f ( z ) ( 1 − f ( z ) ) have at most finitely many common zeros.
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More suggestions(15)
many common antiseptics
many common infections
many common goals
many common diseases
many common variants
many noninvertible zeros
many common substances
many needless zeros
many common parts
many common weeds
many common words
many positive zeros
many common species
many common causes
many common misconceptions
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com