Sentence examples for ln l from inspiring English sources

Exact(47)

For l ′ (x) = 0, ∂ ∂ x ln l ( x ) should be zero because l(x) > 0 for all x.

The statistic associated with this test is defined as: l = - 2 lnL = - 2 ln L H 0 L H 1 = - 2 ln L H 0 - ln L H 1 (7).

The Weibull model provided the best relative fit (lnL = − 49.954), whereas the gamma had an intermediate fit (ln L = − 49.957) and the lognormal had relatively poor fit (ln L = − 50.384) to the Kachchh catalog.

From assertion (3) of Lemma 3.3 and the above inequality, we have ln l 1 − < u 1 ( t 1 m ) < ln l 1 +.

Then, after implicit differentiation we have l ′ ( x ) = l ( x ) · ∂ ∂ x ln l ( x ).

In computation, we use the Davidon-Fletch-Powell method to minimize – ln L (Fletcher and Powell, 1963).

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Similar(13)

The difference in congruence log-likelihood (Δ-ln L) of the tree topologies was determined and compared for the 7 ML trees.

Subsequently, the unconditional log-likelihood can be written as the sum of the individual log-likelihood contributions: L=sum limits_{i=1}^Nleft{{c}_{li}ln {l}_{1i}+{c}_{2i}ln {l}_{2i}+{c}_{3i}ln {l}_{3i}+{c}_{4i}ln {l}_{4i}+{c}_{5i}ln {l}_{5i}-ln {D}_{0i}kern0.5em right} where c si  = 1 if l si is the contribution of individual i to the likelihood, and c si  = 0 otherwise.

Within C. jejuni there was no evidence of congruence with the likelihood values (-ln L) for all of the single locus trees within the range of -ln L values generated for random trees (Figure 2B).

Furthermore, a linear relationship between ln(¯¯¯L/¯¯¯¯M−0.24w)−ΔE/RTc and T0m/TcΔT is observed, implying that the crystal growth is dominated by a secondary nucleation.

To determine this, we conducted a LR test based on following specification: LR=-2times left(ln {L}_P-left(ln {L}_d+ln {L}_Cright)right) (5).

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