Sentence examples similar to l the problem from inspiring English sources

As stated in [22], we define the spectral radius of L as the basic reproduction number R_{0}^{D}:=rho(L) for the problem (2.1).

It is well known that the principal eigenvalue (lambda_{1}(L)) of the problem left { textstylebegin{array}{l} - phi_{xx}=lambdaphi, quad x in 0, L), phi=0, quad x=0, x=L end{array}displaystyle right.

During the searching scope [τ min,τ max ], there are τ i, i=1,2,…,L so that the problem (12) will be operated L times.

If L = 1, the problem reduces to SMV.

"As soon as l learned about the problem, we acted without hesitation.

In this section we discuss the stability of the solution, respectively, in C and L 2 for the problem (5.1).

Along with L we consider the problem (L^ = L^(Q x), h)) in the form begin{aligned}& ell^ Z := -Z" + Z Q x) = lambda Z, quad x > 0, end{aligned} (6) begin{aligned}& U^(Z) := Z'(0) - Z(0)h = 0, end{aligned} (7) where Z is a row vector.

(2) The boundary value problem (1.1) and (1.2) has at least two positive solutions for each parameters ((a,b inLambda ^{E}setminus L); the boundary value problem (1.1) and (1.2) has at least one positive solution for ((a,b in L); the boundary value problem (1.1) and (1.2) does not have a positive solution for any ((a,b inLambda^{N}).  .

The boundary value problem (1.1) and (1.2) has at least two positive solutions for each parameters ((a,b inLambda ^{E}setminus L); the boundary value problem (1.1) and (1.2) has at least one positive solution for ((a,b in L); the boundary value problem (1.1) and (1.2) does not have a positive solution for any ((a,b inLambda^{N}).

Let Q denote the operator in L p ( 0, 1 ; l q ) generated by the problem (32 - 33 32 - 33

and u 2 is a solution of the problem ( L + λ ) u = 0, L k u = f k − L k u 1. (3.15).