Sentence examples for l parallel to from inspiring English sources

Let L be a linear segment of length l, parallel to the y-axis.

Namely, equality in (4.3) or (4.4) implies all of the chords of K and L parallel to u have midpoints that lie in a hyperplane, respectively.

Then equality in both (4.3) and (4.4) holds; thus all of the chords of K and L parallel to u have midpoints that lie in a hyperplane, respectively.

(4.6) If the inclusion is an identity, then all of the chords of K and L parallel to u have midpoints that lie in a hyperplane, respectively.

Thus we see that all of the chords of K and L parallel to u have midpoints that lie in a hyperplane, respectively, for all (uin S^{n-1}), namely, K and L are ellipsoids.

end{aligned} (4.4) Equality in (4.3) or (4.4) implies that all of the chords of K and L parallel to u have midpoints that lie in a hyperplane, respectively.

The " L n, 2 " inductance, in parallel to L n, 0, contains two terms which are both proportionate to | ϵ 1 | − 2. The first term is negative and simply modifies the net inductance by a small correction, making the net inductance appear bigger as the ac flux increases.

The length of the basin (L b) measured parallel to the main drainage line, i.e., from west to north-east direction and is 21.8 km.

Thus, due to SVD, the MIMO channel can be viewed as N L parallel fading channels, and for lth layer, the kth received symbol that corresponds to ({s_{k}^{l}}) in the transmitter can be expressed as {r}_{k}^{l} = sqrt {{rho_{l}}} cdot {s}_{k}^{l} + {n'}_{k}^{l}.

Although the Rake receiver is considered to be optimal, unfortunately it needs L parallel correlators which make its implementation unfeasible for practical UWB channels.

(HK4) For each point-line pair ( P, l ), P ≁ l, there are at least two non-neighboring lines through P parallel to l. (HK5) There exist a hyperbolic plane H ∗ = ( P ∗, L ∗, I ∗ ) and an incidence structure epimorphism φ : H → H ∗ such that P ∼ Q ⟺ φ ( P ) = φ ( Q ), ∀ P, Q ∈ P, l ∼ d ⟺ φ ( l ) = φ ( d ), ∀ l, d ∈ L. and if [ g, h ] = 0 then φ ( g ) ∥ φ ( h ) (see [5]).