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Hence that the function λ ( t ) = sup { λ f, g ( t ) : f, g ∈ D 1 ( R + γ, ε ) } (3.10). is also convex on [ 0, 1 ], and consequently, it is a continuous function on [ a, b ].
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In [6], it is also shown that when f is a continuous function, it admits as an approximation the symmetric subdifferential defined and studied in [16].
It means that (mathcal{G} z)) is a continuous function for each (zin C [0,T])).
As the sets (Lambda_{i}), (iin I), are disjoint, open and closed, it follows that (H_{mathcal{S}}(f)) is a continuous function.
Proof It easy to check that (P_{e}) is a continuous function of (theta ).
It is known that if f is a continuous function from T × E w into E w, then the function t ↦ f ( t, y ( t ) ) is Pettis integrable for every AC function y : E → E (see [[28], Lemma 15]).
Since (a(t)in L^{1}(0,1)) is nonnegative, (G t, s)> 0) is continuous on ([0, 1]times[0, 1]), and (f:[0, 1]times[0, infty]rightarrow[0,infty)) is a continuous function, it is easy to see that (Tu(t geq0). So (T Krightarrow K) and T are continuous. Let (Phisubset K) be bounded, i.e., there exists a positive constant M such that (f t,u leq M) for all (tin[0, 1]), (uin Phi).
Since is a continuous function and, it is easy to see that.
It is also easily seen that h is a continuous function.
For applications of Gabor frames, it is essential that the window g is a continuous function with compact support.
It is well known that the index is a continuous function on the set of semi-Fredholm operators.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com