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Exact(36)
Next, we prove that (I_{lambda}) is unbounded from below.
Therefore, the functional (E_{lambda,mu}) is unbounded from below.
Hence the functional (I_{lambda}) is unbounded from below.
Finally, we prove that (I_{lambda}) is unbounded from below.
Now, we will verify that I is unbounded from below.
Then (I phi,psi)) satisfies the (PS) condition and it is unbounded from below.
Similar(23)
Here the nonlinear term is a sign-changing continuous function and may be unbounded from below.
Note that these non-degenerate potentials (q(t)) may be unbounded from below.
Throughout this paper, we consider the time scales which are unbounded from above and have a minimum point.
there exists ρ, R > 0 such that I± u) > R, if ∥u∥ = ρ; I± u) are unbounded from below.
The nonlinear term in the boundary value problem is sign-changing and may be unbounded from below.
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