Suggestions(2)
Exact(3)
Thus (Theta_{n} phi)) is contraction for each (ngeq1).
Now we show that (Theta_{n} phi)) is contraction for all (ngeq1).
In [1] the authors gave an example of a map which is contraction for but not for the euclidian distance.
Similar(57)
JANET No, Chrissy, the apostrophe-s is not possessive, it's contraction for "three IS company".
Who's is the contraction for who is.
"sup" is a contraction for "What's up?".
"DMS" is the contraction for "domestic monitor system", and is designed to be driven passively in the home setting – it incorporated a crossover within the loudspeaker cabinet.
That is, (phiinmathcal{K}(W,V)) if ϕ is a contraction for a single norm (vert cdot vert ).
An isometry is a contraction for which ∥ T x ∥ = ∥ x ∥ for every x ∈ H.
Repeating this argument, we can show that (Gamma^{n}) is a contraction for n large enough.
From the restriction (a), we see that is a contraction for each.
Write better and faster with AI suggestions while staying true to your unique style.
Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com