Exact(26)
The operator (mathcal{H}_{1}) is continuous by the continuity of f.
It is easy to get that A is continuous by the continuity of f.
To this end, from the hypothesises (H 2) (1) and (3), one can prove that F is continuous by the continuity of g and of the operator f.
which is continuous by Lemma 2.8.
Moreover, ℱ is continuous by (3.6).
Since F and g are compatible mappings and g is continuous, by (25) and (26).
Similar(33)
As Achilles's trajectory must be continuous, by the definition of continuity (applied to instant t = t* = 1 P.M).
Such functions are continuous by definition.
Condition (ii) is satisfied automatically, as solutions to (TVP) are continuous by construction.
For each normal input arc a p, t), the place p must be continuous by definition.
Temporally, the two groups are continuous, by virtue of sharing isolates in 1989.
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