Sentence examples for integration of the first from inspiring English sources
The algorithmic framework is an integration of the first order non-convex majorization-minimization method and the second order non-smooth Newton methods.
From here and by integration of the first equation of system (1) we get we have x ( t ) ≥ F ∫ T 1 t a y α Δ τ ≥ F L α ∫ T 1 t a ( ∫ T 1 τ b ( s ) Δ s ) α Δ τ. (9).
Integration of the first row of (21), using the given boundary conditions and I i = I ( η i , yields c ∫ 0 θ max G d θ = ∫ 0 θ max ∑ i = 1 3 σ i I i η i d θ = ∫ 0 π / 2 I ( t ) d t. (24).
The area under the TAC of each organ was generated using the following strategy including trapezoidal integration of the first four TAC data points through the origin and exponential decline of the four remaining TAC data points to infinity such that the residence times of these organs were obtained [40].
An integration of the first equation of model (4) yields begin{aligned} frac{x t -x_{0}}{t} &=varepsilon +omega bigllangle x(t)y(t) bigrrangle - delta bigllangle x(t) bigrrangle +frac{x t -x_{t} int_{0}^{t}{t(s)y(s),dB(s).
These data further suggest that integration of the first two TM regions is inefficient.
The integral intensities were calculated by double integration of the first-derivative EPR spectra.
Integration of the first-order component leads to the general solution begin{aligned} y=exp {left( frac{small 1}{small 3}leftC_2+2displaystyle C_2+2dintlaystylexpnt exp {left( -C_1x-frac{small 1}ofmall 3}x^3right) }dxright) end{aligned}of (12).
A vertical integration of the second type (b) takes place within firms of the 63 NACE sub-industry, for example offering storage activities, and firms of the transport sub-industry.
Integration of the third row of (21) with the given boundary conditions and substitution of (24) yields r ∫ 0 π / 2 I ( t ) d t = ∫ τ 1 τ 2 I ( t ) d t. (26).
The second unknown is the target chromaticity value y T. Integration of the second row of (21) using the given boundary conditions and substitution of (24) yields 1 / y T ∫ 0 π / 2 I ( t ) d t = ∫ 0 π / 2 I ( t ) / y ( t ) d t. (25).
