Sentence examples for integration above from inspiring English sources

And while Europeans have the legal right to move freely in search of jobs, in practice imperfect cultural integration — above all, the lack of a common language — makes workers less geographically mobile than their American counterparts.

Each can be vertical or horizontal (see the discussion of interdisciplinary integration, above).

The integration above can be evaluated in a closed form with the generalized Cauchy-Binet formula (see, e.g., [7, Corollary ]).

For geographical networks of mobility, R&D activities and patent citations we cannot detect any substantial progress in European research integration above and beyond the common global trend.

Following Favell's definition of a public philosophy of integration above, this paper distinguishes between two ideational levels on which to trace stability and consensus: normative and causal ideas.

In Fig. 5 a and b, the posterior is almost entirely located in the domain of integration (above the dashed and dotted lines), whereas in Fig. 5 c, most of the posterior and in Fig. 5 d almost the entire posterior is outside this area (below the dashed and dotted lines).

The other variable that was sought to trigger integration from above is societal pressure.

It should be noted that, despite the positive effects of regional integration presented above, some criticisms have been aired as well.

Indeed, he argues that as societies evolve institutions that encourage what Henrich et al. call aggregate market integration (discussed above), their utility functions and social norms tend to converge on self-regarding economic rationality with respect to welfare.

With integration of above equation, we have first-order kinetic equation: {text{Ln}}frac{{left[ {4{text{-CP}}} right]_{0} }}{{left[ {4{text{-CP}}} right]_{t} }} = K_{text{app}} t, (18 where [4-CP]0 and [4-CP] are the concentrations of 4-CP at the beginning and time t, respectively.

The integration of above equations under the boundary conditions that n 1, n el 1, n eh 1, v x 1, v y 1, v z 1, φ 1 → 0 as ξ → ∞ yields the following phase velocity relations λ 0 = v x 0 sin θ + v z 0 ± 1 + 2 T i T eff - n d 0 n el 0 + n eh0 - 1 Φ i 0 1 - Φ i 0 1 + T i / T eff 1 - Φ i 0 - 1 1 + n d 0 n el 0 + n eh 0 - 1 Φ i 0 1 - Φ i 0 1 + T i / T eff 1 - Φ i 0 cos θ. (22).