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Then, integrating the above integral equation from to, noticing that and, we have (2.10).
(51) Integrating the above equation with respect to x once and setting integration constant to zero yield {{phi }_{t}}+int{f ( {{phi }_{x}} ), d{{phi }_{x}}}+{{ bigl( g ( {{phi }_{xx}} ) bigr)}_{x}}=0.
Integrating the above equation with respect to x once and setting integration constant to zero yield {{ ( ln w )}_{xt}}+6delta {{ bigl( {{ ( ln w )}_{xx}} bigr)}^{2}}+delta {{ ( ln w )}_{xxxx}}=0.
Integrating the above two Eqs.
Integrating the above relation, we obtain (3.5).
Integrating the above inequality from 0 to, we have (2.5).
Integrating the above inequality with respect to time yields (2.27).
Integrating the above expression in [ 0, 1 ] yields (3.4).
Integrating the above from to, we get (2.15).
Integrating the above from to, by (2.4) we get (2.21).
By integrating the above inequality on, we get (3.5).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com