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Multiplying both sides of (16) by H ( t, a 1 ), then integrating it from a 1 to t φ ( a 1 ), and using integration by parts, we obtain.
By integrating it from to, we have (3.52).
Integrating it from 0 to t, we have x Δ ( t ) = ∫ 0 t y Δ τ.
Then by Lemma 3.2, (3.4) holds and integrating it from to we get (3.9).
By taking in (2.8) and then integrating it from to, we get (2.9).
By taking in (2.11) and then integrating it from to, using the definition of in (2.1), we get (2.12).
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Instead of saving the chorus for climactic effects in the finale, as in his Second Symphony (and as in Beethoven's Ninth), Mahler integrates it from the very beginning into the complex and many-hued vocal and instrumental colours eight soloists, a boys' choir, two large choirs of mixed voices able to project powerful antiphonal effects with orchestra and organ.
At first, we multiply (sqrt{x^{2}+4}F_{m}(x)) to both sides of (14), then integrate it from (-2i) to 2i.
It can be seen from Eqs. (20) and (18) that F ′ and Θ (hence f ′ and θ decay exponentially as η → ∞. We multiply Eq. (7) by f and integrate it from η to ∞, obtaining ε 1 f f ″ − ε 1 2 f ′ 2 + f 2 f ′ = 0. (21).
By the idea in [15], we take v ∈ H k T 1 and multiply the two sides of the equality d ( e Q ( t ) P ( t ) u ˙ ( t ) ) d t + e Q ( t ) B u ˙ ( t ) + e Q ( t ) ( 1 2 q ( t ) B − A ( t ) ) u ( t ) + e Q ( t ) ∇ F ( t, u ( t ) ) = 0. by v and integrate it from 0 to kT.
Multiply (2.5) with (lambda=lambda_{n}) by (tilde{varphi } x,tilde{lambda}_{n})) and (2.7) with (lambda= tilde{lambda}_{n}) by (varphi x,lambda_{n})) (in the sense of scalar product in (mathbb{R}^{2})), respectively, subtract the two equations and integrate it from (x_{n}^{j}) to (x_{n}^{j+1}).
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com