Sentence examples for integral leads from inspiring English sources

Putting λ = i s gives the local approximation to the steepest descent trajectory, and integrating the resultant approximation to the integral leads to the asymptotic solution ψ n j ∼ f j A j 2 π t ρ 0 ″ exp ( − [ n w − v p t ] 2 2 t ρ 0 ″ v p 2 ).

Evaluation of the spatial integral leads to a quantity that is now taken to represent the change in kinetic energy of the mass resulting from the action of the force and is just one-half the vis viva.

In the zero temperature limit a Sommerfeld expansion of the Fermi-Dirac integral leads to (8).

Then evaluating the convolution integral leads to the following covariance function, (4) where and is the temporal separation between two input points, (see Boyle and Frean (2004) appendix for derivation and generalization to multidimensions).

Diagnostic MR imaging near the implant location is affected by image artifacts extending 40mm from the SPG Neurostimulator, including the integral lead, with a spin and gradient echo pulse sequence.

The stimulating electrodes on the integral lead are positioned within the PPF proximate to the SPG, with the body of the SPG Neurostimulator positioned on the lateral-posterior maxilla medial to the zygoma and anchored to the zygomatic process of the maxilla using the integral fixation plate.

The SPG neurostimulator) was implanted so that the stimulating electrodes on the integral lead were positioned within the PPF proximate to the SPG, with the body of the SPG neurostimulator positioned on the lateral-posterior maxilla medial to the zygoma and anchored to the zygomatic process of the maxilla using the integral fixation plate).

Using of half-order derivatives and integrals leads to a formulation of certain real-world problems in different areas [1, 6].

The micromechanical formalism, based on the kinematic integral equation, leads to the computation of effective storage modulus and its associated loss factor in the quasi-static domain.

Notice that the overlap integral s≠0 leads to an energy shift of the main resonant absorption peak given by δ≈2s2|t|/(1−s2)≈100 meV.

The consideration of integral conditions leads to establish a class of linear multipoint schemes for the numerical solution of boundary value problems for ordinary differential equations.