It is therefore important in any survival study to ascertain not only the extent of loss to follow-up, but also its independence of the probability of death.
This lack of independence affects the probability of type I errors (ie, erroneous declaration of statistics significance), and makes it difficult to gain clear inference on the nature of missingness, as illustrated in our Results section.
It is well documented that offspring mass at the time of nutritional independence affects the probability of survival in many animals and is a crucial variable in population growth [ 22, 30- 32].
For our study's case-control ratio of one to five, independence in the probability of exposure among cases and controls, and a type 1 error probability of 5%, our a priori estimates of power were 89% for ischaemic stroke, 99% for acute myocardial infarction, 71% for venous thromboembolism, and 99% for congestive heart failure to detect a clinically important unadjusted odds ratio of 1.5.
A value chain is proposed for propagating the tolerances from the customer domain through the functional, physical, and process domains while maintaining independence and maximizing the probability of success (axioms one and two).
Given a sequence of (K graphonemes, (Q {F,G})), rather than assuming independence between symbols, the probability of the joint-sequence, (P(Q(F,G))), can be estimated using the so-called "n-grams" [5] (sequences limited to (n) symbols).
Formally, we assume that the additive response conforms to Bliss independence [20], [21]; the probability of infection (or disease, depending on the vaccine) in the presence of an immune response to a mixture is the product of the probabilities of the infection in the presence each separate immune response.
whereas, assuming independence for different colluders, the probability of detecting at least a colluder can be estimated as in (44).
and, assuming independence for different colluders, the probability of detecting at least a colluder is estimated as P_{d} = 1 - (1 - P_{d,text{single}})^{C}. (44).
In our case, given a frame of length t and taking into account the independence of Z i, the probability of having i urns (slots) with one ball (tag) is P ( λ, t ) = t i P ( Z = 1 ) i ( 1 - P ( Z = 1 ) ) t - i = t i ( e - λ λ ) i ( 1 - e - λ λ ) t - i. (15).
