Sentence examples for increasing processing rate from inspiring English sources

Extensional viscosity of all grades studied was found to decrease with increasing temperature and increasing processing rate.

A greater flow of ozone and agitation of the ozonated water system also increased processing rates.

Decreasing stretching rate or increasing processing temperature was found to eliminate this glassy photoelastic regime leading to the observation of a linear initial stress optical behavior past a temperature of 95 °C (Tll).

This "rate effect" has been attributed to the increasing processing demands in M1 (Lutz et al. 2005).

This increased digital processing rate is required to faithfully represent the nonlinear operators which enlarge the available input bandwidth, thereby requiring a larger digital processing rate.

We found that functional islet grafts display increased processing and relatively lower proinsulinemia at rest, with an inability to increase their processing rates further when stimulated.

But this dramatically increases processing time.

Hence, the proposed data mitigation technique is much lower in complexity compared to signal DPD, which in turn can be unfeasible in large bandwidth satellite systems due to the increase of processing rate.

It is found that remapping history data references increases the GPU processing rate when histories start to complete.

The induced new transform and quantization architecture greatly increases the data processing rate and eliminates transform multiplication and transpose memory, and select different mode and quantization according to AC coefficient, DC coefficient, chrominance block and Luminance block.

To analytically understand the observed saturation of crRNA upon k increase, it is straightforward to derive (see Methods) the relative increase of crRNA, as pre-crRNA processing rate is increased from k to k': (0.5) Δ p p = λ s / k + 1 λ s / k ' + 1 − 1 From the above equation, it follows that as k' becomes significantly larger than λ s (i.e. k ' ≳ 10 λ s ), Δ[ p]/[ p] no longer depends on k'.