Sentence examples for in order to split from inspiring English sources

Hand Lebanon back to Mr Assad in order to split Syria from Iran? Surely not.

Basically, you can share your ride home with someone else on your route in order to split the cost.

Our leader then did something technical (I'm not good with technical concepts myself) in order to split the early Internet in half: a hundred persons over here, another hundred over there.

That was noteworthy because Assad's enemies have often accused him of tolerating Isis or tacitly cooperating with it in order to split rebel ranks and present himself as a secular bulwark against al-Qaida and jihadi fanaticism.

In initial reactions, leaders of the Tel Aviv tent camp dismissed Mr. Netanyahu's promises as insufficient and accused him of trying to bribe the students in order to split the protest movement.

The law says Alitalia would have to go through a procedure similar to bankruptcy in order to split itself in two and have its debt stay with one half, says Edoardo Staunovo Polacco, a lawyer who specialises in bankruptcy.

In addition, Mercedes was ordered to split the cost of the tribunal equally with Pirelli and the F.I.A.

This is only a rough story; in order to precisely split out the agglomeration effect into its parts we need to rely on the instrument in our next analysis.

The span of the whole region was selected in order to subsequently split the region into 50 kb non-overlapping bins (Table  1).

In order to select split channels for transmissions, Arikan has provided a set of formulas [8] to calculate the Bhattacharyya parameter of each split channel, that is: left{begin{array}{l}Zleft({W}_N^{2i-1}right)=-Z{left({W}_{N/2}^iright)}^2+2Zleft({W}_{N/2}^iright) Zleft({W}_N^{2i}right)=Z{left({W}_{N/2}^iright)}^2end{array}right.

In order to solve split equality feasibility problem (1.2), Moudafi [11] introduced the following simultaneous iterative method: left { textstylebegin{array}l} x_{k+1} =P_{C}(x_{k}-gamma A^(Ax_{k}-By_{k})), y_{k+1} = P_{Q} y_{k}+beta B^(Ax_{k+1}-By_{k})), end{array}displaystyle right.