Operators were urged to "enter every station as if there is a pair of yellow lanterns at the entrance," a scenario that would call for trains to observe a speed limit of 10 miles per hour, and for operators to sound a horn.
We say that is of type if there is a pair providing such that.
A function t:[0,1]→[0,1] is a transformation function, if there is a pair of similarity model s and distance function d s.t.
What they obtained is the existence of at least one solution if there is a pair of upper and lower solutions.
However, one might object to the preceding reply on the grounds that if there is a pair of coexistent necessarily omniscient and necessarily morally perfect omnipotent agents, then there is a pair of incompatible contingent states of affairs each of which is morally optional for these agents, that is, neither morally prohibited nor morally required for them.
A numerical method applied to the equation (1.1) is said to be exponentially stable in the mean square, if there is a pair of positive constants β 1 and β 2 such that the numerical approximations Y n satisfy E | Y n | 2 ≤ β 1 E | x 0 | 2 e − β 2 ⋅ n Δ t, n ∈ N, (3.9).
If there is a pair of candidates that does not form a winning coalition, that is, for some (forall (i,j in {1,2,3}^2), (v_i+v_j<1/2), the compound lottery would not include the simple lottery (x_{{i,j}}) as an outcome of the compound lottery.
Given a formula (phi in mathcal {L}), we say that it is satisfiable if there is a pair ((mathcal {M},omega)), where (mathcal {M}={Omega,P and ω∈Ω, such that ((mathcal {M},omega models phi ); otherwise, we say ϕ is unsatisfiable.
A mild solution of system (1) is said to be exponentially stable in mean square if there is a pair of positive constants λ, (M_{0}) such that mathbb{E} biglVert x t,t_{0},phi) bigrVert ^{2} leq M_{0} e^{-lambda t-t_{0})}.
The equation (1.1) is said to be exponentially stable in the mean square if there is a pair of positive constants α 1 and α 2 such that for any initial data x 0 ∈ L F 0 2 ( Ω ; R d ), E | x ( t ) | 2 ≤ α 1 E | x 0 | 2 e − α 2 t, for all t ≥ 0. (3.8).
