Sentence examples for i proof from inspiring English sources
The Tox21 collaboration began formally in 2008 with Phase I (Proof of Concept) consisting of qHTS studies conducted at the National Institutes of Health Chemical Genomics Center (NCGC) in 1,536-well format 1,536-well formatt studies conducted in support of the U.S. EnvironmentandProtection Agency's (EPA) ToxCast™ program.
During Tox21 Phase I (proof of principle), many biochemical and cell-based assays were successfully developed and miniaturized in a 1,536-well 1,536-wellat for screening against the initial Tox21 collection of aplateimately 3,000 compounds in a quantitative high throughput screening (qHTS) platformatShukla et al. 2010; Tice et al. 2013).
25 The first results with this biologic agent in patients with psoriasis came from a randomized Phase I proof-of-concept clinical trial involving 36 patients diagnosed as having chronic plaque-type psoriasis.
Mutagenesis was performed using i-proof Taq polymerase (BioRad) according to the manufacturer's directions.
The weak user's data constraint is active and data arrival to the weak user occurs at time t i. Proof.
x i ?. Proof The topology of ( X, ∥ ⋅ ∥ ) is induced by the cone metric d ( x, y ) = ∥ x − y ∥ and the topology of ( X, ⦀ ⋅ ⦀ ) is induced by the metric ρ ( x, y ) = ⦀ x − y ⦀.
The following holds: if (W -1) ij ≠ 0, then there exists some directed path j → i. Proof.
then the boundary value problem (1.1) has at least one solution on I. Proof.
Definition 3.1 A continuous solution of the integral equation (3.1) is called a mild solution of the nonlocal problem (1.1), (1.2) on I. Theorem 3.2 If the assumptions (H1)∼(H4) hold and W ( t ) = u ( t ), then the problem (1.1), (1.2) has a mild solution on I. Proof Let Z = C ( I, X ) and Z 0 = { u ∈ Z : u ( t ) ∈ Λ τ, t ∈ I }.
Lemma 3 The inequality f ( ( x 1 ∗ ⋯ ∗ x n ) ( 1 / n ) ∗ ) ≤ ( f ( x 1 ) ∘ ⋯ ∘ f ( x n ) ) ( 1 / n ) ∘. holds for all n ∈ N and x 1, …, x n ∈ I. Proof It is clear that the lemma holds for n = 1.
for all x ∈ I. Proof According to Theorem 2.1, it suffices to verify that the inequality (15) holds for all x ∈ I.
