Sentence examples for i m m from inspiring English sources

USIC ∗ + ( I, m, M ) is a closed subset of USIC + ( I, m, M ).

We first prove the case of USIC + ( I, m, M ).

Lemma 2.4 Suppose that φ ∈ X ( I ; m, M ).

since p ij = m i m M p Mj = m i m M p j using the same notation as in Section 'High average power approximation (HPavA)'.

The same applies to the case of USIC ∗ − ( I, m, M ).

Thus, by Theorem 4.1, Eq. (5.1) has a unique solution F ∈ USIC − ∗ ( I, m, M ).

The capacity of the C i BBUs constraint requires that ∑ s ∈ S m i s b s ≤ C i, ∀ i ∈ M, m i s ≥ 0, m i = ( m i 1, m i 2, m i 3, …, m i s ) (2).

where G m ≜ ∑ i ≠ m M ̄ ρ i g ̂ i g ̂ i H.

Then, it is not hard to show that G m = ∑ i ≠ m M ̄ g ̂ i g ̂ i H meets G m 2 = G m, which suggests G m is an idempotent matrix.

Then, the solution can be proposed a finite power series in Y in the form: u = S ( Y ) = ∑ i = − M M a i Y i, Open image in new window (23).

Step 2. Suppose the solutions of (10) can be expressed by a polynomial in ϕ in the form [17, 18]: u = ∑ i = − m m α i ϕ i , α m ≠ 0, (11).