Sentence examples for i e l from inspiring English sources

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Again, to guarantee neutrality of the electrolyte, we must have C h e l + C i e l = C 0 e l.

The condition ξh = ξi, deduced from point (iv), applied to each of the two media, yields C i S i C h S i = C h e l C i e l ≡ R C = exp e 2 K B T W h − W i (14).

In particular, we wish to determine the concentrations of ions and holes in the two media far from the interface (outside of any space charge region), which we denote by C h S i, C i S i, C h e l, and C i e l, respectively.

Again, to guarantee neutrality of the electrolyte, we must have C h e l + C i e l = C 0 e l.   (iii) Since there are no currents at equilibrium, the electrochemical potentials must be constant; in particular, they must be the same in the two bulk media for each species.

where M i e l i ( x ) Open image in new window are the minimal polynomials of α i e l i Open image in new window, for l i = 1,2,⋯,n i −k i, where each α i e l i = ( β i e l i, β i e l i, ⋯, β i e l i ) Open image in new window.

Compute the mean between e u (i) and e l (i); that is, μ(i) = [ e u (i) + e l (i)]/2.

For two M L neurons coupled with synaptic inhibition, the equations for voltage V and K activation variable w are given by C d V i d t = I app − ( g ¯ L ( V i − E L ) + g ¯ K w ( V i − E K ) + g ¯ Ca m ∞ ( V i ) ( V i − E Ca ) + g j → i H ( V j − V th ) ⋅ ( V i − E syn ) ) d w i d t = w ∞ ( V i ) − w i τ w ( V i ) (2.1).

Then, we define E S = { e i, j | 1 ≤ i ≤ N C, 0 ≤ j ≤ n i }, E L = { e L k | 1 ≤ k ≤ N A },    E = E S ∪ E L. In a prototype chromosome graph, a path might visit two edges in E L contiguously.

Bayesian factor and CMS were calculated as follows: B F = ∏ i = 1 n P S i | s e l e c t e d P S i | n e u t r a l (9) C M S = ∏ i = 1 n P S i | s e l e c t e d P S i | s e l e c t e d × π + P S i | n e u t r a l × 1 - π (10)in which the Greek π was the prior probability of selection, being estimated from prior information of the data.

18: end if l i = m a p T r u s t L e v e l ( E i, T i ).