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Theorem 3.6 shows that for (nge 3), (nne 4) the set of the dimensions of the groups that can act properly on (X) has a lacuna of size linear in (n) located immediately below the maximal possible dimension.
Corollary 4.7 is analogous to Theorem 3.6 and shows that for (Nge 3) the set of the dimensions of the groups that can act properly on (X) has a lacuna of size linear in (N) located immediately below the second largest dimension (N^2+2N-1).
In Group B, the articular surface was smoother than before but still has a lacuna.
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"Reporting Civil Rights" has a few lacunae (where's Gunnar Myrdal?), but the most important absence is of material hostile to the civil-rights movement.
The idea of this limbo, these years in which she both did and did not exist, has created a lacuna in her sense of self, as she explains to a stranger: "'Those frozen years, they're still with me.
(underline{lim}_{n rightarrowinfty} frac{varphi(n) - frac{10}{3}{sqrt{n}{n}} = sqrt{frac{2}{3}}); if ({ {mathcal{A}}_{k} }_{kinmathbb{N}^) is a family of σ-algebras and each algebra ({mathcal{A}}_{k}) has (varphi k)) lacunae, then this family has a full set of lacunae.
For each (n in mathbb{N}^), denote by (frak{v}(n)) the minimal cardinal number such that if ({mathcal{A}_{lambda }}_{lambda in Lambda }), (#(Lambda ) = n), is a family of algebras, and for each (lambda in Lambda ) the algebra (mathcal{A}_{lambda }) has (frak{v}(n)) lacunae, then the family ({mathcal{A}_{lambda }}_{lambda in Lambda }) has a full set of lacunae.
Then this family has a full set of lacunae.
Assume that the family (mathfrak{A}') has a full set of lacunae ({U^{1}_{lambda},U^{2}_{lambda}}_{lambdainLambda}).
We must prove that this family has a full set of lacunae.
In this paper we deal mostly with the following problem: under which conditions a family of algebras ({mathcal{A}_{lambda }}_{lambda in Lambda }) has a full set of lacunae.
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Justyna Jupowicz-Kozak
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