Sentence examples for had the same index from inspiring English sources
The French National Institute of Statistics and Economic Studies found that France had the same "index of human development" (material well-being) as Belgium and Denmark, but polled much lower in the "happiness scale," which ranged from one to ten: France was 7.2, while Belgium scored 7.7 and Denmark rated 8.3.
If individuals had the same index date in two or more databases, they were identified first in the physician database, then in the hospital, then RAI-MDS, and lastly the drug database.
Since and have the same index and null-space by Theorem 1.2, their ranges have the same codimension.
In our scheme, the common keywords in different documents for a certain group have the same index values.
This rule says that two formulae to be conjoined must have the same index before the rule of conjunction introduction can be used.
The author required that f 0 has the same index of differentiability and integrability with respect to variables x and v, i.e., they are isotropic.
In this paper, we discuss the robustly chain transitive set, and show that the robustly chain transitive set is hyperbolic if and only if every periodic points in the set is hyperbolic and has the same index.
there is a (C^{1} -neighborhood (mathcal{U}(f)) of f such that for any (ginmathcal{U}(f)), any periodic point of (Lambda_{g}(U)) is hyperbolic and has the same index; there is a (C^{1} -neighborhood (mathcal{U}(f)) of f such that for any (ginmathcal{U}(f)), (Lanyda_{g}(U)) is hyperiodic.
Let (f|_{Lambda}) be robustly chain transitive in U. Then following conditions are equivalent: (a) there is a (C^{1} -neighborhood (mathcal{U}(f)) of f such that for any (ginmathcal{U}(f)), any periodic point of (Lambda_{g}(U)) is hyperbolic and has the same index; (b) there is a (C^{1} -neighborhood (mathcal{U}(f)) of f such that for any (ginmathcal{U}(f)), (Lanyda_{g}(U)) is hyperiodic. .
Each thread, including those that are in the border area, copies the value of the grid point with opposite parity that has the same index to the shared memory.
