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He had rank in an upper caste.
Vann was providing both, because Vann had rank and credentials.
The original context has rank 1.
We have rank(D =rank=t.
First, we prove that W n ⋆ has rank one provided that Ψ nn ⋆ has rank one.
Furthermore, rank(B 1)≠0, so we have rank(B 1)=1.
Here, the optimal solution will have rank N, however.
(4) The matrix A has rank at most 2.
Then we prove that indeed Ψ nn ⋆ has rank one.
Tautologies have rank 0 and contradictions are infinitely surprizing.
Similarly, we have rank(B 2k )=rank(B 3)=rank(B 4 =1.
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