Sentence examples for gains corresponding from inspiring English sources

The on-line computational burdens are reduced by pre-computing off-line the sequences of state feedback gains corresponding to the sequences of nested ellipsoids.

The PID controller gains are formulated as the optimal state-feedback gains, corresponding to the standard quadratic cost function involving the state variables and the controller effort.

The critical gains which correspond to a pair of poles entering the right-half of the s -plane and the optimal gains corresponding to locating the closed-loop poles at the left extreme of the root-locus for each vibration mode are determined.

Then, classical augmented NMF factorization with MU rules is applied to estimate the gains corresponding to each source j in the multichannel mixture.

The indices of the fading gains corresponding to the erased blocks are collected in the set E = { E 1, …, E e }, E i ∈ { 1, …, m r } ).

In [22], it was shown that K/2 DoF are achievable when the cross-link channel gains corresponding to the interferers are rational, whereas the direct-link channel gains corresponding to the intended signal are irrational algebraic; if the direct-link channel gains are rational as well, the DoF of the channel are strictly smaller than K/2.

Thermogravimetric analyses of the residual powders showed a mass gain corresponding to 2 4% residual active metal content, suggesting the combustion of the intermetallic RMNPs in the spray flame was nearly complete.

Filtering this representation through the family of sub σ-algebras generated by the multivariate point process of system components, we consider the innovation gain corresponding to the dynamics of component i.

The relative gain corresponding to the setups in Fig. 3 is shown in Fig. 4.

Since data coding results in an effective power gain, corresponding convolutional coding gain (Gc) and repetition coding gain (Gr) must be applied to obtain an effective SNR for the implementation of the AMC scheme in mobile wireless networks.

With K ¯ n the stationary gain corresponding to P, the DARE is P = F - 1 N ∑ n = 1 m K ̄ n H n β n P F - 1 N ∑ n = 1 m K ̄ n H n β n T + 1 N 2 ∑ n = 1 m K ̄ n R n K ̄ n T β n 2 + G G T, where GGT = Q.