Sentence examples for for service j from inspiring English sources

Exact(11)

( overline{R_{b_j}} ): average data rate for service j.

where: ( {R}_{{mathrm{b}}_{mathrm{ji}}}^{mathrm{Min}} ): minimum data rate for service j of VNO i, ( {R}_{{mathrm{b}}_{mathrm{ji}}}^{mathrm{Max}} ): maximum data rate for service j of VNO i. ( {R}_{{mathrm{b}}_{mathrm{ji}}}^{mathrm{Min}} ): minimum data rate for service j of VNO i, ( {R}_{{mathrm{b}}_{mathrm{ji}}}^{mathrm{Max}} ): maximum data rate for service j of VNO i.

( {W}_{ji}^{Srv} ): weight of serving unit of data rate for service j of VNO i, where ( {W}_{ji}^{Srv}in left[0,1right] ).

( {R}_{{mathrm{b}}_{mathrm{ji}}}^{mathrm{Srv}} ): serving (allocated) data rate for service j of VNO i; N VNO: number of VNOs; N srv: number of services.

where W SRb : weight for session average data rate, where W SRb  ∈ [0, 1] ( overline{R_b^{max}} ): maximum average data rate among all network services ( overline{R_{b_j}} ): average data rate for service j.

( {R}_{b_{ji}}^{mathrm{Srv}} ) is the serving data rate for service j of VNO i, R b is the vector of serving data rates, N VNO is the number of served VNOs, N srv is the number of services for each VNO, and.

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Similar(48)

If there is not a trusted service node i that has interacted with the feedback node j directly, it needs a recommendation node k to recommend a trusted node j for service node i.

en-queue j for service while bandwidth available.

Using the information in S, we then calculate the similarity of m i with other patterns that have the information for target service s j.

Each ekj in the matrix E, represents the expectations of server time for service k execution on cloud resource j, and it takes a weighted average of the history data Ekj, as shown in formula (10).

If G j is the Grade of Service (GoS) required for ISG j services, then the overall partitioning problem can be described as the definition of the vector m j = (m1, m2, …mk 1), which satisfies inequalities (1) and (2): P b, j A j, m j ≤ G j, ∀ j ∈ 1, k − 1 (1) ∑ j = 1 k − 1 S j 0 ≤ C min (2).

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