Sentence examples for for any paths from inspiring English sources

Exact(1)

Howe had previously ordered a scout to look for any paths through the swamp, but Campbell's route, which was shown to the British commander by a slave, remained unknown to the Patriots.

Similar(59)

Congress is in the midst of considering an immigration reform bill that demands more of this deadly deterrent strategy – $4.5bn more – as a condition for any path to legalization for the estimated 11 million immigrants currently living in the country without working papers.

It can be easily shown that the Doppler shift for any path (i) is given by (4) or (5) [14] 14].

A connectivity function computes a value f(π a ) for any path π a, usually based on arc weights.

For any path the weight of the start and end points depend on the height of these points.

Thus, complex polygonal domains induce in large number of triangles, edges and vertices in the visibility graph, thus representing a challenging search space for any path-planning algorithm.

In Path's case, it lets you sign in with Facebook, your address book and other sites to cross-reference them for any Path user who you're already friends with elsewhere.

It can be defined by the associated parallel transport: for any path between (a,bin G) it sends ({T_a} G) to ({T_b} G) by the differential of the left multiplication by (ba^{-1}).

As we observe from Figure 2 for any path of vertices < x0, x1, x2,..., x m >, the queue size vector of each vertex in the path has to be component-wise larger or equal to the queue size of any other vertex that succeeds it in the path and the queue size vectors of any two vertices on the graph cannot be the same.

Specifically, for single-path routing, the median throughput gain is up to 60%%, and for each source-destination pair, the throughput gain is as high as 5.3×; for any path routing, the maximum per-flow throughput gain is 71.6 %, while the median gain is up to 13.2 %.

The above integral exists in the sense that for any path ω with a subexponential growth z 1, z 2 solve the following Itô equations: d z 1 + ν z 1 d t = d W 1 ( t ), d z 2 + λ z 2 d t = d W 2 ( t ).

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