Sentence examples for for any partitioning from inspiring English sources

Exact(1)

The approach relies on the use of a simulation tool, capable of estimating the performance for any partitioning configuration exploiting a model of the target architecture and the profiling results.

Similar(59)

For any partition P∈Ω, this surrogate problem needs to be solved.

According to a theorem he proves (1994: 185), U A) = ∑i P(Si)U(A given Si) for any partition of states.

The set of constraint 4 states that the traveling distance (time) to a subset A j ∈P for any partition P∈Ω cannot exceed the maximum allowed distance (time).

If Δ φ ( x i, y j ) ≥ 0 ( i = 1, 2, …, m ; j = 1, 2, …, n ) for any partition of P, then it is said that φ ( x, y ) satisfies the condition Ω in D [14].

For (Iin{{mathbb{R}}}_{{mathcal{F}}}), the function f is fuzzy Henstock integrable on ([a,b]) if for any (varepsilon>0) there is a function (delta: [a,b ]to{{mathbb{R}}}_) such that for any partition δ-fine P, (D (sum^{n}_{i=1}{ (x_{i}-x_{i-1} )odot f ({xi}_{i} ),I} )<varepsilon ).

Theorem 2. There exists an h ̄ > 0 Open image in new window such that for any partition J h with 0 < h < h ̄ Open image in new window, the linear system (20) has a unique solution V ~ i p Open image in new window for 1≤i≤N and p=1,2,….

This relation is stated by the following lemma: (see the former reference for the proof) For any partition ( ℋ 0, ℋ 1 ) of the observation space V N, the probabilities of type I and II errors satisfy L ( P Y ∣ X N ; P Z ∣ X N ) ≥ α log α 1 − β + ( 1 − α ) log 1 − α β. (59).

Given an i.i.d outcome X N =x N with composition, or type P X, for any partition of the observation space ( ℋ 0, ℋ 1 ), the probabilities of type I and II errors satisfy L ( P Y ∣ X ; P Z ∣ X ∣ P X ) ≥ 1 N α log α 1 − β + ( 1 − α ) log 1 − α β. (65).

Plateau length, n ≥ 6, is considered as good support for any partition.

The distance measure defined here has a theoretical minimum of 0; however, this value will not be the true lower bound for most annotation systems, as even having 1 protein with 2 different annotations (perhaps due to its being composed of multiple non-overlapping domains) will not allow the H (K | C f ) term to go to 0, for any partition of the proteins.

Show more...

Ludwig, your English writing platform

Write better and faster with AI suggestions while staying true to your unique style.

Student

Used by millions of students, scientific researchers, professional translators and editors from all over the world!

MitStanfordHarvardAustralian Nationa UniversityNanyangOxford

Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak quote

Justyna Jupowicz-Kozak

CEO of Professional Science Editing for Scientists @ prosciediting.com

Get started for free

Unlock your writing potential with Ludwig

Letters

Most frequent sentences: