Your English writing platform
Discover LudwigExact(58)
for any j with 1 ≤ j ≤ n.
However, the ANN is able to provide values for any J, and not just discrete values.
For any j ∈ {1, 2,..., n}, there exist constants,, and such that.
If {(P s > P t ) OR (I j > I th (for any j))}.
Therefore, for any j ∈ J, μ j = 0, which implies that J is finite.
Then for any ( j in [1,; ldots,;N_{Obj} ] ), we have.
By complete induction, it follows that ⋃ n = j ∞ A 0 n is not closed for any j ( ∈ Z 0 + ) ≤ k.
The parameter γ was set to 100, and the initial values of the state variables at (t = 0) were chosen as (x_{j}^{0} = 10) for any j.
In the inequalities (29), we put f ( x ) = − ln q ( x ) and x j = 1 r j for any j = 1, 2, …, n, then we obtain the statement.
Similar(2)
Let A be a complete chain of vectors; then, the following conditionsare equivalent: (1) for any j∈Z functions ω j (t) are continuous on ; (2) limit values at the boundary points of supp ω j are zero for all j∈Z. . for any j∈Z functions ω j (t) are continuous on ; limit values at the boundary points of supp ω j are zero for all j∈Z.
Moreover, for any (j', j in[J]), (j'leq j"), the set (bigcup_{jin[J]: j'leq j leq j"}sigma_{j}) is arcwise connected.
Write better and faster with AI suggestions while staying true to your unique style.
Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com