Sentence examples for for a le from inspiring English sources

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With $6,000 already raised just hours after the fundraiser opened, and backers able to pledge everything from $15 for a Le Guin badge to $1,000 for a one-minute recording from the author responding to a query on writing or life, Curry said the Kickstarter "seems to be doing well so far".

(mathbf{F5}^) ({mathscr {T}}(r) rightarrow infty ) uniformly for (a le F r) le b) as (|r|rightarrow infty ).

Note that upon setting (s=sup r^{2} dot{{mathscr {G}}}^{2}(r)) for (a le r le b), a sufficient condition implying (3.13) is the strict inequality gamma ( n-1 + s ) < frac{ n-2)^{2}}{4} + 2. (3.17) In case ofrac{ n-2ichlet energy (i.e., (F(r, t) equiv t)) it is easily seen that (overline{d}{ underline{d}) and so (gamma=1).

Moreover, the ODE for ({mathscr {G}}), that is, (2.20) can be integrated to give the solution ({mathscr {G}}(r) = (2pi m + z) mathscr{N}(r)) for (a le r le b) where the profile (mathscr{N}) is described by (cf. (2.18)) mathscr{N}(r) = frac{(r/a)^{2-n} - 1}{(b/a)^{2-n} - 1}, quad ngeq3.

For (a le t le s le b), we easily know that biglvert H t, s bigrvert le frac{Gamma 2-beta)(s-a)}{Gamma 2-betabeta)(b-a)^{1-beta}} leqfrac{Gamma(2-beta)(b-a)}{Gamma(alpha-beta)(b-a)^{1-beta}} = frac{Gamma(2-beta)(b-a)^{beta}}{Gamma(alpha-beta)}.

It should be noted that, for (a le b le c), (a,b,c inmathbb{R}), a triangular fuzzy number (u = (a,b,c)) is given such that (underline{u} alpha)=a+ (b-a alpha) and (overline{u}(alpha)=c- (c-b-a alphaand the endpoverline{u} alphat for all (alpha in [0,1]).

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For a Les Paul guitar, you will need wood, as listed below.

"Plywood has a rich history in design," Drumm says, reaching for a heavy Le Corbusier catalogue.

In the reference scenario, the discounted cost, for a population LE of 81 years, was estimated at €5 831 (€888 for the medical consultations plus €4 942 for L-carnitine supplementation).

"It makes an excellent plot for a Le Carré novel".

The operator (J^{alpha }), defined on the usual Lebesque space (L_{1}[a,b]) by begin{aligned} begin{array}{ll} J_{a}^{alpha }f(x)=frac{1}{Gamma (alpha )}int _{a}^x (x-t)^{alpha -1} f(t){rm d}t J_{a}^{0}f(x)=f(x) end{array} end{aligned}for (a le x le b), is called the Riemann Liouville fractional integral operator of order (alpha ).

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