Sentence examples for finite limits from inspiring English sources

Exact(59)

It can be proven that the two terms of (3.36) converge to finite limits, and analyze each.

Moreover, if we have another good model prefibration (mathcal {C}' rightarrow I) and functor (Phi :mathcal {C}rightarrow mathcal {cartesianesian over I and such that (Phi (i)), (i in I) preserve finite limits, then we have a natural isomorphism begin{aligned} Phi ' circ U^dagger cong U^dagger circ Phi.

the function (V t,x)) is a continuous on (J/{t_{k} in J}timesDelta) and it is locally Lipschitz with respect to its second argument; for each (s_{k} in J) and (x inDelta) there exist finite limits V(s_{k},x =V(s_{k}-0,x)= lim_{t uparrow s_{k}}V t,x) quad text{and}quad V(s_{k}+0,x)= lim_{t downarrow s_{k}}V t,x).

They will form a mental map based on a world with finite limits and no easy answers.

Moreover, in contrast to the situation with physical injury, there are no necessary finite limits on the number of persons who might suffer emotional injury as a result of a given negligent act.

Further, we have generalized the Gauss quadrature method by considering the case of finite limits of integration, which we show to be important when considering heavy oils.

The Fortuny dome and the cyclorama became essential tools of the scenic illusionists, but their invention served the anti-illusionists equally well, as they gave a sense of space beyond the finite limits of the stage, gave solidity to the stylized decor, and silhouetted the rhythmic action of the players against a background of diffused light.

First, when all the states are subjected to constraints, we employ a Barrier Lyapunov Function (BLF), which grows to infinity whenever its arguments approach some finite limits, to prevent the states from violating the constraints.

The non-zero finite limits q appear as the zeros of certain entire analytic functions, one particular function for each fluid or solid region in the medium (and also for each Riemann sheet in the presence of homogeneous half-spaces).

For finite limits, the argument is exactly the same.

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In this Hilbert space we define the operator A with domain D(A):=left {textstylebegin{array}{l} f:f(x) mbox{ and } D^{alpha}f(x), ^{c}D^{alpha}f(x) mbox{ are absolutely continuous } mbox{on } [-1,0 cup 0,1], mbox{ and } f(0pm),D^{alpha}f(0pm),I^{1-alpha}f(0pm) mbox{ have} mbox{finite limits}, L_{i}f=0,i=1,2,3,4.end{array}displaystyle right } and action law Af:=mathfrak{L}_{alpha,x}f.

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