Sentence examples for f b l from inspiring English sources

As shown in relation 8, half of the capacity of a room is decreased if it is split: S ic Z icbf + X ijlt − 1 M ≤ ∑ r ∈ R bf Ca p bfr y icbfrlt − 1 2 ∑ r ∈ R bf Ca p bfr W bfrlt ∀ i, j ∈ J i, c ∈ C i, b, f, ∈ F b, l, t ∈ T l.

Therefore (11) is used to calculate C F b l u, v, 0 ≤ l < k.

The proposed blocking metric was used as a decision criterion, and the proposed NR image quality metric was computed as follows: I Q M N R = w 1 1 + w 2 1 × F B L K, w 1 2 + w 2 2 × F B L R, F B L K ≥ t h ( Blocking exists ) F B L K < t h ( No Blocking ) (15).

The coefficients C F b l u, v and the estimation function defined in [6] are used to segment the coefficients C F b k u, v in the two clusters.

The proposed IEOL-based fusion rule can be described as follows: f F L ( x, y ) = f A L ( x, y ) i f : IEOL A L ( x, y ) > IEOL B L ( x, y ) f B L ( x, y ) i f : IEOL A L ( x, y ) ≤ IEOL B L ( x, y ) (18).

Then, the range of target is expressed as R = f b c 2 K = cT 2 B f b (5).

By interpolation [8] between (2.10) and the following relation: ∥ F 0 ∥ L x 2 L t 2 = ∥ f ∥ L τ 2 L ξ 2, we immediately obtain for all b > 5 8 r − 2 r ∥ F b ∥ L x r L t r ≤ C ∥ f ∥ L τ 2 L ξ 2.  □.

The space B S p ( R, X ) of all Stepanov bounded functions, with the exponent p, consists of all measurable functions f : R → X such that f b ∈ L ∞ ( R, L p ( [ 0, 1 ] ; X ) ), where f b is the Bochner transform of f defined by f b ( t, s ) : = f ( t + s ), t ∈ R, s ∈ [ 0, 1 ].

I'm making no value judgements, but what I will say is this: -4: Jimenez (12), Z Johnson (3) -3: Cabrera-Bello (11) -2: Stenson (F), Westwood (F), Woods (F), B Watson (7), D Johnson (7), Snedeker (6), Cabrera (2) 3.56pm BST Cabrera-Bello races his par putt at 11 a mile past the hole, and drops back to -3.

Consider the MSE P l + p = E { ε l + p ε l + p T } in which we substitute the estimate x ̂ n + p with (36), P l + p = E { [ F l + p ε l + p − 1 + B l + p w l + p − K l ( z l − H l Y l x ̂ l + p − 1 ) ] T }. (111).

In the simplest case, F is linear in b such that begin{aligned} F(b)=F_0left( 1-f_1 bright), end{aligned} (4.11 where (F_0) and (f_1) are positive constants.