Sentence examples for exists a component from inspiring English sources

Exact(6)

Then there exists a component in which joins with, and (1.8).

There exists a component F α ( u ) of F ( u ) such that m ⊂ F α ( u ).

There exists a component, say (H_{i_{0}}) ((i_{0}in{ 1,2,ldots, p})) that has a pendant vertex.

If there exists a component function (f_{i}:[0,T]timesmathbb{R}^{3}timesmathbb{R}^{3}rightarrow mathbb{R}) such that (f_{i}) is always positive or negative on its domain, then equation (1.1) with periodic boundary condition or Neumann boundary condition has no solution.

Then there exists a component T in ∑ which joins to , and Proj R T = [ ρ ∗, + ∞ ). for some ρ ∗ > 0. Moreover, there exists μ ∗ ≥ ρ ∗ > 0 such that (1.1) has at least two positive solutions for μ ∈ . Here T joins to such that lim ( μ, u ) ∈ T, ∥ u ∥ ≤ 1 μ → ∞ ∥ u ∥ = 0, lim ( μ, u ) ∈ T, ∥ u ∥ > 1 μ → ∞ ∥ u ∥ = ∞.

More precisely, there exists a component Σ 0 of positive solutions of (1.1), (1.2) which meets [ λ ˜ 1 ( a 0 ), λ ˜ 1 ( a 0 ) ] × { 0 }, where λ ˜ 1 ( a 0 ), λ ˜ 1 ( a 0 ) will be defined in Section  4; (iii) If (H 4) and (H 5) also hold, then there is a number λ ∗ > 0 such that problem (1.1), (1.2) admits no positive solution with λ > λ ∗.

Similar(54)

Because of the maximal connectedness of (mathscr{D}^), there does not exist a component (mathscr{D}^{ast}) of (overline{mathcal{U}}capmathscr {S}^) such that (mathscr{D}^{ast}cap D^neqemptyset), (D^{ast }cap partialmathcal{U}capmathscr{S}^)neqemptyset).

There are 6 connected components and, among them, there exists a giant component (the largest connected components) consisting of 3,435 proteins (99.57% of the total number of proteins) and 7,251 interactions (98.43% of the total number of interactions).

Let S and S ′ be two minimal separators of a graph G. Then S and S ′ are parallel if and only if there exists a full component C S of G − S and a connected component C S ′ of G − S ′ such that C S ⊆ C S ′.

If (G=langle phi _1,phi _2,ldots,phi _nrangle) where each (phi _i in mathcal {E}_k) for every (1 le i le n) and let (Omega _G) be a Fatou component of G. Then for any (phi in G) there exists a Fatou component of G, say (Omega _{phi }) such that (phi (Omega _G) subset bar{Omega }_{phi }) and begin{aligned} partial Omega _Gsubset bigcup _{i=1}^n phi _i^{-1}(partial Omega _{phi _i}).

In particular, Theorem 5.3 in [7] gives an example of a polynomial semigroup (G=langle phi _1,phi _2, ldots rangle) in (mathbb C), such that there exists a Fatou component, (say (mathcal {B}), which is conformally equivalent to a disc), that is wandering, but returns to the same component infinitely often.

Show more...

Ludwig, your English writing platform

Write better and faster with AI suggestions while staying true to your unique style.

Student

Used by millions of students, scientific researchers, professional translators and editors from all over the world!

MitStanfordHarvardAustralian Nationa UniversityNanyangOxford

Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak quote

Justyna Jupowicz-Kozak

CEO of Professional Science Editing for Scientists @ prosciediting.com

Get started for free

Unlock your writing potential with Ludwig

Letters

Most frequent sentences: