Your English writing platform
Discover LudwigSuggestions(1)
Exact(2)
If C r and P ( G σ ) have exactly one common arc, then d = n − 3. Let e = ( u, v ) be the unique arc of C 4 which has no common vertices with P ( G σ ).
For example, the (MC) entails that if two variables have exactly one common cause, and neither is a cause of the other, then the two variables will be screened off by their common cause.
Similar(58)
Denote by (X^{0}(n,t)) the n-vertex cactus consisting of t triangles and (n-2t-1) pedgest edgesuchch that triangles and pendent edges have exactly one vertex in common.
The line graph (mathcal{L}(G)) of a graph G is the graph whose vertices are the edges of G, with two vertices in (mathcal {L}(G)) adjacent whenever the corresponding edges in G have exactly one vertex in common.
You can't apply exactly one example to another country but there are common themes.
Paths in some groups were identical except for exactly one customizable path component, while paths in other groups shared a common repetitive subpath.
To prove that is weakly convergent to a common fixed point of, it now suffices to prove that consists of exactly one point.
Let K be the complete oriented graph on the finite set of vertices A. A family G="{Ga:a∈A} of spanning subgraphs of K is an orthogonal cover provided every arrow of K occurs in exactly one Ga and for every two elements a,b∈A, the graphs Ga and Gopb have exactly one arrow in common.
One common problem with fringe projection is the fact that the its intensity pattern has to be exactly sinusoidal.
Exactly one: Jan Morris.
has exactly one positive solution.
Write better and faster with AI suggestions while staying true to your unique style.
Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com