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"Shouldn't the second equation read 16 over pi?" asks Gabriella.
Published 12 September 2014 In the published article text, a term was omitted from Equation 2. This equation read: Pr [ Z = z | A = a, q ] = (2 z + a − 1 z ) q z + a (1 − q ) z It should have read: Pr [ Z = z | A = a, q ] = a a + z (2 z + a − 1 z ) q z + a (1 − q ) z The article has now been corrected.
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The time-dependent Schrödinger equation reads The quantity i is the square root of −1.
Thus, the error equation reads mathcal{Q}_{k} e_{k+1}= e_{k}.
Thus, the integral equation reads as u = ∫ M d θ = ∫ 1 b θ − 1 d θ = 1 b log θ, (1).
Without making any assumption about the paint rheology, neglecting gravity, the mechanical equilibrium equation reads − ∇ p + ∇ ⋅ σ ¯ ¯ = 0, (1).
and the corresponding equation for the Green's function in the energy representation, The last equation reads in (x,y) representation and with the convention (10).
end{aligned} (8)The Schrödinger equation reads begin{aligned} left[ frac{p^2}{ 2 mu } +frac{1}{2} mu w^2 ( i sqrt{ 1 + beta p^2 } partial _p )^2 right] psi = E psi.
The equation reads as follows [25]: u t + α u u x + u x x x − ( u u x x ) x − b u x u x x = 0. (1.1).
For this problem, the corresponding Riccati equation reads left{begin{array}{ll} dP s)&=(R+P s))^{-1}Lambda^{2}(s ds+Lambda(s dW s),quad sin [0,T], P T &=G, end{array}right.
kern-0pt} 3} ) and the corresponding GKP equation reads frac{partial }{partial x}left( {frac{partial u}{partial t} + alpha frac{partial }{partial x}left( {frac{1}{3}u^{3} } right) + beta frac{{partial^{3} u}}{{partial x^{3} }}} right) + gamma frac{{partial^{2} u}}{{partial y^{2} }} = 0, (16).
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