Sentence examples for equation amounts from inspiring English sources

The method presented is based on a self-similar change of variables technique to transform the Kolmogorov Equation into a new form, such that the problem of designing structure preserving schemes, for the original equation, amounts to building a standard scheme for the transformed equation.

In all cases the applicability of the Wheeler Jonas has been demonstrated, i.e. one can use this equation to extrapolate single laboratory breakthrough results by simply varying the independent variables of the equation (amount of adsorbent, flow rate, inlet and breakthrough concentrations).

It was never really clear what the "Don't Ask" side of the equation amounted to.

The saponin content was calculated according to the equation: amount of saponin (mg/g) = weight of residue/weight of sample.

The residue which is the crude alkaloid was weighed and calculated according to the equation: amount of alkaloid (mg/g) = weight of precipitate/weight of sample [ 22].

The average consumption of sevoflurane was calculated using the following equation: Amount of sevoflurane used (mL) ÷ 3.3 ÷ vaporizer flow rate (L/min) ÷ duration of administration.

All ICS were compared using the following equation: total amount of a drug/DDD of a drug = number of DDDs [ 18].

Values for the amount and percentage of a constituent extracted by the subject were calculated for each pair (used and unused) of samples according to the following equations: Amount extracted = Quantity in unused pouch − Quantity in used pouch Percentage extraction = 100 × Amount extracted / Quantity in unused pouch.

Finding the state d ^ with minimum energy in Equation 1 amounts to the estimation problem with MAP.

Trivially, equation (1.3) amounts to the conjunction of begin{aligned} &mathbb{P}biggl(S_{n}-frac{a_{0}}{1-a_{1}}n mu >xbiggr)lesssimfrac{na_{0}}{1-a_{1}} overline{F}_{X}(x quad text{and} &mathbb{P}biggl(S_{n}-frac{a_{0}}{1-a_{1}}nmu >xbiggr gtrsim frac{na_{0}}{1-a_{1}} overline{F}_{X}(x), end{aligned} (3.1) which will be proven separately in the following two subsections.

Using the language of section 5, the solution of the electronic Schrödinger equation (which amounts to using the BO adiabatic separation) for R = − R0 11.9yields the minimum electronic energy level splitting in Figure 42b and consequently the ET matrix element as | Vs(− R0, Qt) – Va(− R0, Qt)|/2.