Sentence examples for e corresponding to from inspiring English sources

Two site conditions were considered: soil class C and soil class E, corresponding to firm and soft soil deposits, respectively.

(h_{g}^{e}) is the distance between the extreme solutions of PFref and E, corresponding to the gth objective function.

Central soft tissue density on T1 (arrowhead in lower image part) with no contrast enhancement (arrowhead in e), corresponding to squamous debris.

namely γ is an eigenvector of the linear operator ( J α ) ∗ : C T ( E ) → C T ( E ) corresponding to the simple eigenvalue 1.

The function x : J → E is said to be Pettis integrable on J if and only if there is an element x J ∈ E corresponding to each I ⊂ J such that φ ( x I ) = ∫ I φ ( x ( s ) ) d s for all φ ∈ E ∗, where the integral on the right is supposed to exist in the sense of Lebesgue.

The local network coding coefficients, β e, e ′ ( t ) 's and αe,v(t)'s, are real-valued, and the determination of their value will be discussed in Section 4. The quantizer operator, Q e, corresponding to outgoing edge e, is designed based on the values of C e and L, and the distribution of its input (i.e., random linear combinations).

These groups are labelled (a-e) corresponding to the similarly labelled groups in Fig. 7, and in each case an example network from the group is depicted alongside the label.

Finally, the number of decoys was increased from about 36 in DUD to 50 decoys per ligand in DUD-E, corresponding to about 2%% actives for each target, and their properties improved to have the same average net charge as the actives.

Two peptides, numbered 1, M-A-A-P-G-G-R-S-E-P-P-Q-L-P-E, corresponding to the first 15 amino acids (1 15) and peptide 5, L-D-V-Q-D-E-A-M-R-T-L-A-S, corresponding to the last 13 amino acids (768 780) of the human pendrin sequence (Everett et al, 1997), were synthesised by the conventional solid phase method, and used to prepare antipeptide antisera in rabbits.

Furthermore, the eigenvectors e V and e M corresponding to λ d become e V d and e M d, respectively.

In this case, both events e j and e k corresponding to κ1 and κ2, respectively, are found.